filtr adaptacyjny do rekonstrukcji sygnałów stereofonicznych
Transkrypt
filtr adaptacyjny do rekonstrukcji sygnałów stereofonicznych
! ! " ##$#% &'()*% (+ ,!-.!.!- 2003 Poznañskie Warsztaty Telekomunikacyjne Poznañ 11-12 grudnia 2003 ! " # # $ ! # #% / 0 . . -0 1 -( . - ( . ! 2 0 .( . . 0 -/ /- - - ( 0+ ( ! 3 $ / . 0 0 4 / /1 .05 ( . 0! 6 .78 . 1 -0( -/ 9: -/ 9 ; ( - . 0 /1 - - 1 - . 0:! ( - 0 -07 0 ( . - ( - ! < 1 70( - ( 0 / -/ . ( ! 2 0 9=": . . / 05 ( 0 5 -/( 05 0 7( . /1 0 0 / ! > 0?! @( - 5 -001 -/ -/ ! - 0 - ;75 0 17 . 9 0 -/: - 0 ; 07 =" 0 -/ 05 ( 01 >- 1? 0. 7! -/ . .5 -0 8 1 -;5 A ! ;( 0 / ; . . 0 / 1 -!+ /( 4 1! 05 -- - BCD BED -/ 9": 178 ( 5 . ; > 8? - .( 05. 9 92 ::! " ; 5 ; 9-. - 0 ( : . 7 0 5 / ! 2 ; 8 -- . . /( . . 7 0 ( 0 - 7 - ="! 05 - - -. 0/0 -/. . . /-7 --( 05. / 1- 05. - ="! "1- ( 05 92: 9 1 ; . 0 0 -( 2: . 05. -/ . 1 9:! @ - ( -/ / -/ - ( -/ - 05. =" 9 - - -/ 0 0 0 0 - .:! - ( - ; ( 8 2 1 0 1 ( =" -05 "! ( 0 =" ; 8 05 ( -0 / -0! . -- ; 8 ( .05 F A 7 -/ 5 -4 ! -- 0 0 .( / A - 5 - 5 0 ! " ! ! " # C [N × N ] k ! k ∈< 1, N > $ C<k| % C|k> C<k|k> = (C<k| )|k> = (C|k> )<k| [N − 1 × N ]% [N × N − 1] [N − 1 × N − 1] C k % k k k & " & $' % & " (y(t)) (s(t)) * (z(t)) % T % + y(t) = yL (t) yR (t) % s(t) = T T sL (t) sR (t) % z(t)= zL (t) zR (t) % L R ,&$' & (y(t)) (s(t)) & ' + y(t) = s(t) + z(t) sL (t) zL (t) yL (t) = + , yR (t) sR (t) zR (t) -./ zL (t) ∼ N (0, σz2 ), zR (t) ∼ N (0, σz2 ) 0 L R R(t) z(t) R(t) = σz2 σzLR L E[z(t)z(t)T ] = . 0 σzRL σz2 R (s(t)) & &$'+ s(t) = s(t) + n(t) p nL (t) sL (t) aLi sL (t − i) i=1 = + , p sR (t) nR (t) i=1 aRi sR (t − i) -1/ aL1 , . . . , aLp % aR1 , . . . , aRp 2 p% n(t) = T nL (t) nR (t) ! * -nL (t) ∼ N (0, σn2 L )% nR (t) ∼ N (0, σn2 R )/ 0 0 T & z(t) -E[n(t)z(t) ] = = 0/ 0 0 0 Q(t) n(t) σn2 σnLR L Q(t) = E[n(t)n(t)T ] = . σnRL σn2 R - L R / ⎡ ⎡ ⎤ ⎤ sL (t) sR (t) ⎢ sL (t−1) ⎥ ⎢ sR (t−1) ⎥ ⎢ ⎢ ⎥ ⎥ ϕL (t) = ⎢ ⎥, ϕR (t) = ⎢ ⎥, ⎣ ⎣ ⎦ ⎦ sL (t−q+1) ⎡ aL 1 ⎢ aL 2 ⎢ ⎢ ⎢ ⎢ θL = ⎢ ⎢ aL p ⎢ 0 ⎢ ⎢ ⎣ 0 ⎡ aR 1 ⎢ aR 2 ⎢ ⎢ ⎢ ⎢ θR = ⎢ ⎢ aR p ⎢ 0 ⎢ ⎢ ⎣ 0 ⎤ sR (t−q+1) q×1 ⎤ ⎡ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥, ⎥ ⎥ ⎥ ⎥ ⎦ q×1 θLT ⎢ 1 0 ... ... ⎢ ⎢ AL = ⎢ 0 1 0 . . . ⎢ ⎣ 0 0 ... 1 0 0 0 ⎥ ⎥ ⎥ ⎥, ⎥ ⎦ q×q q×1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥, ⎥ ⎥ ⎥ ⎥ ⎦ ⎡ ⎢ ⎢ BL = ⎢ ⎣ θRT ⎢ 1 0 ... ... ⎢ ⎢ AR = ⎢ 0 1 0 . . . ⎢ ⎣ 0 0 ... 1 q×1 1 0 0 ⎤ ⎡ 0 0 0 ⎤ ⎡ ⎢ ⎥ ⎢ ⎥ ⎥, BR = ⎢ ⎣ ⎦ q×2 0 0 0 1 0 0 0 0 ⎥ ⎥ ⎥ ⎥, ⎥ ⎦ q×q ⎤ ⎥ ⎥ ⎥, ⎦ 0 q×2 &$ -./ -1/ & ' + AL 0 ϕL (t) ϕL (t − 1) = + ϕR (t) 0 AR ϕR (t − 1) BL nL (t) -3/ , nR (t) BR ϕL (t) T z yL (t) BL BTR = + L . -4/ zR yR (t) ϕR (t) 5 + ϕL (t) AL 0 BL ϕ(t) = , A= , B= , ϕR (t) 0 AR BR 2q×1 2q×2q 2q×2 '+ ϕ(t) y(t) = A ϕ(t − 1) + B n(t), = BT ϕ(t) + z(t). -6/ -7/ % & + T ϕ(0)= ϕTL (0) ϕTR (0) & n(t) z(t) t + T T E[ϕ(0)] = E ϕTL (0) ϕTR (0) = ϕ0= ϕTL0 ϕTR0 , ΣL0 ΣLR0 . E[(ϕ(0)−ϕ0 )(ϕ(0)−ϕ0 )T ] = Σ0 = ΣRL0 ΣR0 8 ! ϕ(t) - ϕ(t) s(t) s(t) . . . , y(1)] = Y(t) = [y(t), yL (t) yL (1) YL (t) ,..., = yR (t) yR (1) YR (t) 4 5 "5 1" " -5 , 1, - - | 0) = ϕ(0) = [y(0), y(−1), . . . ,y(−p +1)]T ϕ(0 | 0) = 0 6 3 Σ(0 | 0) , Σ(0 3 T ! " " "" # $ % | t) = ϕ(t | t − 1) + L(t)(t), ϕ(t & | t−1) = Aϕ(t − 1 | t − 1), ϕ(t ' T | t − 1), (t) = y(t) − B ϕ(t ( T ¹½ L(t) = Σ(t | t−1)B[B Σ(t | t−1)B+ R(t)] , )* T, | t−1) = AΣ(t−1 Σ(t | t−1)AT + BQB | t) = Σ(t | t − 1) − LBT Σ(t | t − 1), Σ(t )) )+ L(t) (t)= , L (t | t−1) L (t) yL (t) T T ϕ = − BL BR R (t | t−1) ϕ R (t) yR (t) " -" " . | t) ϕ(t | t − 1) ϕ(t / - " " % ϕ(t)% L (t | t) ϕ E[ϕL (t) | Y(t)] | t) = ϕ(t = , R (t | t) ϕ E[ϕR (t) | Y(t)] - "- ) (t | t−1) ϕ E[ϕL (t) | Y(t−1)] | t − 1)= L ϕ(t = . R (t | t−1) ϕ E[ϕR (t) | Y(t−1)] | t) Σ(t 0 | t−1) Σ(t " "% " 1" " " ϕ(t) 2- 1" 3 . % | t) = Σ(t 1 σn2 Z(0) = [z(0),z(−1), . . . ,z(−p +1)] , -" ϕ(0) sL (0) s (−1) ϕ(0) = s(t) , L ,..., sR (0) sR (−1) T sL (−p+1) . ! sR (−p+1) ϕ(t) " | t), Σ(t | t)) Y(t)% p (ϕ(t) | Y(t)) = N (ϕ(t 83 3 " ϕ(t) " 5 1" R(t) Q(t) 9 1" 7 3 1 5 3 -5 3 3 "- 4-, 3 . % σn2 R = σn2 L , 3 γC γLR γRL - " κRL κLR κC , Q(t) R(t) - % κL κC 1 γC , R(t) = Q(t) = . γC 1 κC κR / 3 5 % γ , κ , κ , κ , C L R C - - 3 . / . γC - γC = 0 8 3 13" " 5 3 : " 1 : 6 " 1 γC = 1, 0 " . " 5 . - Σ(t | t), ; " - L . "- .- 1 Σ(t | t − 1), σn2 L " Σ(t | t) Σ(t | t − 1) " " R(t) " - 4" Q(t) . " - 1" 5 1 3 " | t − 1) = Σ(t 3 . Q(t) R(t)% , 1 1 γLR Q(t) = γRL γR σn2 L = σnLR /σn2 , γRL = σnRL /σn2 Q(t) = γLR σn2 /σn2 , .- 1 .- < " - .1 . 1- " - " "5 . 5 5 " , " 1- 5 5 γR = "5 " 0 " κL κLR 1 R(t) = κRL κR σn2 L " κ = σz2 /σn2 , κLR = σzLR /σn2 , κRL = L L L L σzRL /σn2 , κR = σz2 /σn2 + / " R L L L R(t) = L R L , , 5 " " , " 7 5 -5 4 ! " # ! " ! ! $ % " ! ! ! ! ! &# γC !# ! # ' 3 ÷ 20 ( 0,7 ÷ 0,1 ! ! & ! ! # & κL " κR " κC ! ! " $ & κC ! $ ! ! " # " !# # # ( ! ! $ κL " κR ) κL *κR + ! $ *+ ! ! ! " , - ! ! ! " " ! $ ! & ! !" κL *κR + ! " # ! " , ! ! " # ! . κL *κR + ! $ & # κL *κR + ! ! ! ! & " ! ! !" , ! ! ,! ! & ! ! !# ! $" κL " κR κC / • ! $ κL " κR κC ! " • 0 *+1" 0*+1 ! " κL (t) = 0 0 0" κR (t) = 0" κC (t) = 0 R(t) = " 0 0 • ! ! " * ! $ ! ! +" " ! # 2 ! # ! ! " # !!" ! $ ! $ 3 κL (t) 4 κR (t) $ *κL (t) = ∞ 4 κR (t) = ∞+ 2 " ! t1 ! t2 ! " R(t1 ) R(t2 ) ! #/ 1) = R(t ∞ 0 2) = , R(t 0 0 ∞ 0 . 0 ∞ 2 ! # * *56++/ ⎡ ⎤ E[sL (t) | Y(t)] ⎢ ⎢ ⎢ ⎢ E[sL (t − q + 1) | Y(t)] | t) = ⎢ ϕ(t ⎢ E[sR (t) | Y(t)] ⎢ ⎢ ⎣ E[sR (t − q + 1) | Y(t)] ⎥ ⎥ ⎥ ⎥ ⎥, ⎥ ⎥ ⎥ ⎦ ! ! / s (t−q+1 | Y(t)) s(t−q+1 | Y(t)) = L | Y(t)) sR (t−q+1 E[sL (t−q+1) | Y(t)] | t) = = CT ϕ(t E[sR (t−q+1) | Y(t)] ϕ L (t | t) = CTL CTR , R (t | t) ϕ ⎡ C = ⎢ CL ⎢ " CL = ⎢ CR ⎣ 0 0 ⎤ ⎡ 0 0 ⎤ ⎢ ⎥ ⎥ ⎢ ⎥ ⎥ ⎥, CR = ⎢ ⎥. 0 0⎦ 1 0 q×2 ⎣0 0⎦ 0 1 q×2 7 ! τ = t−q+1 ' sL (τ )" sR (τ ) ' Y(t) * " Y(t)+ 859 : # ! t ' ! ! ! ! 2 τ ! q −1 ! t" $ sL (τ )" sR (τ ) ! q−1 . ! " # ! ; q−1 ) sL (τ ) 4 sR (τ ) " # ! ! ! q−1 * ! ! + & ! ! ! %< p q > p + 1 ! " # ! " $ q − p − 1 p L R R C | t) = Σ(t | t − 1) = Σ(t C (t | t) Σ L ΣC (t | t) (t | t) Σ C (t | t) , Σ R 2q×2q (t | t − 1) Σ (t | t − 1) Σ L C (t | t − 1) Σ (t | t − 1) , Σ C R # $# ! αL αR αC = = = βL = βR = βCR = βCL = (t−1 | t−1)θ +1 θLT Σ L L (t−1 | t−1)θ +1 θRT Σ R R T Σ θ (t−1 | t−1)θ C R +γC L ΣL (t−1 | t−1)θL <q| (t−1 | t−1)θ Σ R R <q| (t−1 | t−1)θ Σ C R <q| (t−1 | t−1)θ Σ C L L R C R L 2q×2q L∞LR (t) = lim κL (t) → ∞ R L(t) = 0. κR (t) → ∞ *-+ % &" 0 ' ( ! ' $!# &# | t) = ϕ(t ⎡ | t−1) = Aϕ(t−1 ϕ(t | t−1) ⎤ L (t − 1 | t − 1) θLT ϕ ⎢ϕ L (t − 1 | t − 1)<q| ⎥ ⎥. = ⎢ ⎣ θT ϕ R (t − 1 | t − 1) ⎦ R R (t − 1 | t − 1)<q| ϕ <q| *+ ", T T ⎡ Σ(t | t − 1) = ATΣ(t − 1 | t − 1)A + BTQ B =⎤ βL αC βCL αL ⎥ ⎢β ⎢ L ΣL (t−1| t−1)<q|q> βCR ΣC (t−1| t−1)<q|q>⎥ ⎥. ⎢ T T βCR αR βR ⎦ ⎣ αC (t−1| t−1) (t−1| t−1) Σ βCL Σ β C R R <q|q> <q|q> *.+ / " | t − 1) # 0 Σ(t *-+ ", q + 1 # q + 1 $ 1 $ #! q − 1 ' , Σ (t − 1 | t − 1) Σ (t − 1 | t − 1) (t−1 | t−1) ( # Σ(t | t − 1) Σ &" 0 ' ( ! , L C L % ! ! ! # " &" # ' ( )# $& ! !# *Σ (t | t) Σ (t | t) Σ (t | t − 1) Σ (t | t − 1)+ $! *Σ (t | t) Σ (t | t − 1)+, L % ! & 3 κ (t) κ (t) κ (t) ! ! ' ( * ! $ κ (t) = 0 # # + 4 " t # # ! 3 κ (t) = 0 κ (t) = 0 q 5 | t) # $ ' Σ(t 6! $# ! $! $ q & *.+ | t) $ # # Σ(t 0 ' ( $! , T 1 0 ··· 0 0 0 ··· 0 L(t) = 7 0 0 ··· 0 1 0 ··· 0 " $! ' 8 & ' # $ ! & % # !& κ (t) = ∞ κ (t) = ∞ L(t) *2+ &" R C ⎤ αR+κR(t) −(αC+κC(t)) αL αC ⎢ βL βCR⎥ −(αC+κC(t)) αL+κL(t) ⎥ L(t) =⎢ ⎣ αC αR ⎦ (α +κ (t))(α +κ (t))−(α +κ (t))2 L L R R C C βCL βR ⎡ *2+ / " (t | t) ϕ (t | t) ! & ϕ ! ! ! 1 $& # q − 1 0 ! / $!# ! $ ϕ (t | t) (t | t) $!# $ ϕ ! ! # ## $ ! 0 % $ * + $! " 1 ! 9:1 $! ! q − p / & # p ! # ! 8 # !# $ 9:1 & ! &! 0 ; $!# ! !3 L R L R ! κR (t) = ∞ L(t) "#$% L∞R(t)= limκ (t)→∞ L(t) ⎡ R ⎤ αL αC ⎡ 1 ⎢ βL βCR ⎥ αL ⎥⎣ =⎢ ⎣ αC αR ⎦ 0 βCL βR ⎤ ⎡ 1 ⎢ βL /αL ⎦=⎢ ⎣ αC /αL 0 βCL /αL 0 0 0 0 0 ⎤ ⎥ ⎥. ⎦ "#&% ' ( ! ) * " % + * ( ,- L (t). ! ! 0) ! * 6 * ! * 0) * 0 ! "0)% 5000 0 −5000 −10000 0 50 100 150 200 250 300 350 0 50 100 150 200 250 300 350 0 50 100 150 200 250 300 350 5000 0 −5000 5000 0 −5000 | t)=Aϕ(t−1 | t−1)+L ∞R(t)(t) ⎡ T ϕ(t ⎤ ⎡ ⎤ L (t − 1 | t − 1) θL ϕ 1 0 ⎢ϕ ⎢ βL /αL 0 ⎥ L (t) L (t − 1 | t − 1)<q| ⎥ ⎥ ⎢ ⎥ . =⎢ + ⎣ θT ϕ R (t − 1 | t − 1) ⎦ ⎣ αC /αL 0 ⎦ R (t) R R (t − 1 | t − 1)<q| βCL /αL 0 ϕ "#/% ) ! αC ! γC ! 0* )! 0! , #. * * * % *% ! % ! ! ) * * ! !! " *0* % ) 7 . * 1 "300 * % " % 0 ! , # " 0! * 44100 2 )! 16 *% 3, 0 12 γC 0 0,5 1 ) * 4 ,- * * * * ) * 8#9 : ; - < =3> ** > * 3, 3,:3 ? > @@ A : #BB$ CD/CA& ! 0 * * * * 0 0 * 5 * 0! ! 8D9 : ; =E * > = ? 1 F #G#A H* #BB$ I FFF #&@B#&CD 8A9 < -. , J( J( DGGG 8@9 : ; - < =H ? > @B #G 7* DGG# DD&DDD/D