lim x 5[sin(sin x)

lim x
x
0
5
[sin(sin x) − x
1
dx √
x x2 + 1
ˆ
ˆ
dx(1 + x2 )
ˆ
ˆ
ˆ
dx
dx
3/2
x
4 + x4
sinh x
dx √
cosh 2x
dx
ˆ
ˆ
�
19
3
1 x2 ] =
90
1
3x2 − 2x − 1
dx
x+1
x2 + x + 1
x
(x + 1)(x + 2)(x + 3)
ˆ
ˆ
ˆ
dx arctan
�√ �
x
� �
�
dx x2 x2 + 1
dx
arctan (ex )
ex
ˆ
ˆ
√
dx
dx
1
sin x cos2 x
ˆ
dx
cos3 x
sin x
ˆ
dx
1
sin4 x
x+
√
1
x2 + x + 1
x2 + x + 1 = xv + 1